I am working on a Java program that reads a text file line-by-line, each with a number, takes each number throws it into an array, then tries and use insertion sort to sort the array. I need help w...

There are several ways to get input from the user. Here in this program we will take the Scanner class to achieve the task. This Scanner class comes under java.util, hence the first line of the …

May 2, 2010 · You can use java.util.Scanner : import java.util.Scanner; //... Scanner in = new Scanner(System.in); int num = in.nextInt(); It can also tokenize input with regular expression, …

Dec 19, 2012 · There is no API method to get a character from the Scanner. You should get the String using scanner.next() and invoke String.charAt(0) method on the returned String. …

In addition to Scanner(String) constructor, there's also Scanner(java.io.File) among others. Summary Scanner provides a rich set of features, such as hasNextXXX methods for validation.

Jul 10, 2018 · import java.util.Scanner; import java.util.ArrayList; public class Main { public static void main (String[]args) { System.out.println("Introduce the sequence of numbers to store in …

Aug 14, 2011 · I am using the Scanner methods nextInt() and nextLine() for reading input.. It looks like this: System.out.println("Enter numerical value"); int option; option = input.nextInt(); // …

Dec 1, 2013 · scanner.useDelimiter(System.getProperty("line.separator")); You have to check whether there is a next token available and then read the next token. You will also need to …

Sep 15, 2017 · You can use below function that will return you multiple inputs from scanner. public List<String> getInputs(String inputseparator) { System.out.println("You Message here"); …

Aug 1, 2016 · I want to read a double number from standard input, but I always get this exception: java.util.InputMismatchException import java.util.Scanner; public class ScanDouble { public …