Nov 4, 2013 · SELECT V.Customer_id, C.* FROM (VALUES(1), (2), (3)) V(Customer_id) LEFT JOIN Customers C ON C.Customer_id = V.Customer_id Non matching values will have NULL …

Feb 10, 2025 · From the following table, write a SQL query to find customers whose grade is 200. Return customer_id, cust_name, city, grade, salesman_id. Sample table : customer

Jan 22, 2020 · select distinct user_id from user_role r1 where exists (select * from user_role r2 where r2.role = 'add' and r1.user_id = r2.user_id) and exists (select * from user_role r2 where …

If you want to return all columns, without specifying every column name, you can use the SELECT * syntax: Example Return all the columns from the Customers table:

Apr 22, 2019 · We have two tables: The goal is to select [Id] and [CustomerName] of Customers who purchased Milk AND did not purchase Bread. In the case the correct query should return …

To approach this problem, you would use a SQL SELECT statement from the CUSTOMER table, and apply a WHERE clause to filter data for a specific REP_ID.

In this comprehensive guide, we will explore various SQL queries designed for effective customer analysis, aiding your decision-making process and enhancing your business strategies. 1. …

Mar 8, 2025 · From the following table, write a SQL query to find customers whose grade is 200. Return customer_id, cust_name, city, grade, salesman_id. Sample table: customer

The basic SQL statement built to fetch information about the details of certain customers that exist within the Customers table is the select statement as SELECT Name, Email FROM …

Various ways to write. Your query, slightly rewritten to use JOIN and corrected to return all customers in case of ties: select c.*, o.* join orders as o. on o.cust_id = c.cust_id. ( select …