The answer to the original question 'Is it possible to solve for two variables related by single equation ...

Jan 30, 2018 · Solve quadratic equation in two variables . Ask Question Asked 7 years, 3 months ago. Modified 7 years, 3 ...

May 3, 2020 · You cannot solve it for a specific value. It has infinite possibilities. Firstly you need atleast 3 DISTINCT equations if you need to solve for 3 variables. In your question, not only did you provide only 2 equations, both of them are identical, divide by 2 and check. So it's just a single equation in 3 variables.

Jul 2, 2018 · There are two variables so it is not possible to solve it. The equation is homogeneous, and dividing by $y^2$ (*) reduces it to a quadratic $\,t^2-4t+3=0\,$ where ...

Mar 3, 2018 · Use the Euclidean Algorithm to find the gdc of $5$ and $12$. $$12=5\times2+2$$ $$5=2\times2+1$$ Then apply the extended Euclidean Algorithm, (do the initial algorithm in reverse with back-substitution) $$1=5-2\times2$$ $$1=5-2\times(12-5\times2)$$ $$1=5\times5-2\times12$$ Then multiply throughout by $13$ $$13=65\times5-26\times12$$ This gives you a particular solution $(a,b)=(65,26)$.

Jan 8, 2017 · Solving differential equation with two variables. ... solve a differential equation of the following form ...

Sep 2, 2019 · Equations that have only integer solutions (or, in this case, positive integer solutions) are called Diophantine equations. A linear Diophantine equation like $7w+3d=44$ is relatively easy to solve about a quarter of the way through an introductory number theory course. So I'll do some handwaving here at the basic concepts and you know where ...

Dec 11, 2017 · Looking at your first two equations, see if you can produce an equation with no constant term and go from there. $\endgroup$ – Paul Commented Dec 11, 2017 at 15:05

May 15, 2018 · I have a problem where I am to find the intersection between the two curves $$ \begin{cases} x^2 - y^2 = 3 \\ xy = 2, \end{cases} $$ which I can easily see that the two points $\pm(2,1)$ are the real solutions to this problem, but I don't know how to solve for this systematically. I tried two approaches to solve for it as a quadratic equation:

Mar 18, 2016 · I have been trying to solve the following equation, but I am still stuck after trying many different methods. I have been given this equation to solve: $$(1 + z^{-1})^4 (a + bz^{-1} + az^{-2}) -