Jan 12, 2020 · Destroying an object or node in Godot is quite easy. You can call queue_free () in the script that is attached to the node. Or you can call this method on any node reference. You can check if the node is still valid by calling is_instance_valid (node).

Mar 12, 2023 · Try adding an Area2D with an CollisionShape2D to the buildings. Then connect the input_event signal from the Area2D to a script that is attached to the building. Hope this works.

Jul 31, 2019 · queue_free () is essentially a shortcut for destroying a node safely at the end of the frame and also removes it from tree. It does not happen immediately to avoid some tricky situations that would otherwise cause the game to crash.

Oct 3, 2023 · The docs for queue_free () mention use of is_queued_for_deletion (): Use Object.is_queued_for_deletion to check whether a node will be deleted at the end of the frame. But in this situation manually checking should be unnecessary if you first use remove_child() & then queue_free().

Jun 14, 2022 · You can do it on NOTIFICATION_PREDELETE: func _notification(what: int) -> void: if what == NOTIFICATION_PREDELETE: # Assuming these references are still valid (add additional checks otherwise). _level_player.queue_free() _player_combatant_queue_free()

So the queue free method basically cues our node for deletion at the end of the current friend. One thing to note is that with the queue free method when deleted or children nodes will be deleted.

To delete a node and free it from memory, you can call its queue_free() method. Doing so queues the node for deletion at the end of the current frame after it has finished processing.

Mar 17, 2025 · queue_free () is a shortcut for destroying a node safely at the end of the frame and also removes it from the tree. It is useful if we have a node already outside the tree. For example: remove_child () is the opposite of add_child (). It removes the node form the scene tree.

May 7, 2018 · I’ve added multiple instances of a scene as enemies, and now I want to remove one of them when it dies. I tried using “queue_free ()” on it, but this only works for one instance, and every instance afterwards doesn’t get removed and returns a “node not found” error. How do I just remove one instance at a time?

Queues a node for deletion at the end of the current frame. When deleted, all of its child nodes will be deleted as well. This method ensures it's safe to delete the node, contrary to Free (). Use IsQueuedForDeletion () to check whether a node will be deleted at the end of the frame.