With this distance and time value, I can simply plug it into the kinematic equation and solve for the acceleration. This would give an acceleration of 0.1053 m/s 2 .

Question 1: Sketch a graph of velocity vs. time and another graph for position vs. time for this same trip. Be very careful. The common problem is to draw a velocity graph that LOOKS like the ...

Remember, acceleration is the same as gradient, and acceleration = velocity change ÷ time. Look at the graph. The acceleration of the vehicle in the first 10 seconds is: ...

Acceleration = change of velocity ÷ time taken. is the rate of change of velocity. It is the amount that velocity changes per unit time. The change in velocity can be calculated using the equation: ...

Remember the graph shows the fastest car only, and still the average position is around sixth or seventh. The trend through 2010 is one of improvement as the line clearly drops closer toward one ...