The general equation appears as \(Ax + By + C = 0\). However to build up an equation use \(y - b = m(x - a)\) where \(m\) is the gradient and \((a,b)\) is a point on the line.

The straight line through two points will have an equation in the form \(y = mx + c\). Then, we can find the value of \(c\), the \(y\)-intercept, by substituting the coordinates of one point into ...