and acceleration = velocity change ÷ time. To find the distance travelled, look at the area under the graph. In the first 10 seconds this is the area of the triangle, ½ × 10 s × 40 m/s = 200 m.

2}\). A negative gradient shows the rate of 'slowing down' or deceleration. Velocity-time graphs show velocity on the vertical axis. Acceleration is still represented by the gradient.

Since the average acceleration is defined as: The slope of the velocity-time graph is the average acceleration. You can see the fitting equation gives an average acceleration of 6 x 10 4 m/s 2.

How do you integrate with a computer? Let's start with an example. Suppose a car travels only in the x-direction. It starts at x = 0 m with a velocity of 0 m/s. If the car has a constant ...